In Mr. Kelly's √5.
(2[_500
2)[_250
(5[_125
5)[_25
5[_5
1
This works because the pairs are being squared. That means they are square roots that do not need to remain as radicals. (2*5)^2*5=500
This answer is better than a calculator answer because it is more accurate than the calculator. the calculator gives a decimal, and approximation. The calculator answer would be better in instances where you need to see which answers are greater or lesser than. The decimal would also be better to use in science because equipment can only measure to a certain accuracy.
me thod of reducing radicals, you take the smallest factor (other than 1) of the number you are working with. You take down what you get when you divide by that factor Dividing 500 by 2 gives 250, dividing that by 2 gives 125. Next, you divide by 5 because that is the smallest factor of 125. This gives 25, which is then divided by 5, giving 5. When 5 is divided by 5, you get 1. When you hit 1, you're done. Because it is a square root, you find pairs. If it was a cube root, you would find groups of three. This gives pairs of 2s and 5s with one 5 remaining. The pairs go outside the radical as 2*5, and the 5 goes inside. This gives 10(2[_500
2)[_250
(5[_125
5)[_25
5[_5
1
This works because the pairs are being squared. That means they are square roots that do not need to remain as radicals. (2*5)^2*5=500
This answer is better than a calculator answer because it is more accurate than the calculator. the calculator gives a decimal, and approximation. The calculator answer would be better in instances where you need to see which answers are greater or lesser than. The decimal would also be better to use in science because equipment can only measure to a certain accuracy.