(x^y)*(x^z)=x^yz is sometimes true. Most of the time, it is incorrect because when multiplied the exponents should add together, giving an answer of x^y+z. However, if both of the exponents were to be 2, the final answer would be both x^2+2 and x^2*2. This means the equation is true sometimes.
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AuthorI am a runner and I enjoy math. Archives
June 2015
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